JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The mass of non-volatile, non-elctrolyte solute (molar mass \(= 50\,g\,mol^{- 1})\) needed to be dissolved in \(114\,g\) octane to reduce its vapour pressure to \(75\%,\) is .............. \(\mathrm{g}\)
- A \(37.5\)
- B \(75\)
- C \(150\)
- D \(50\)
Answer & Solution
Correct Answer
(C) \(150\)
Step-by-step Solution
Detailed explanation
Molar mass of octane \(=\,114\,g/mol\) From the lowering of vapour pressure we have, \(\frac{{\Delta P}}{P} = \frac{{\frac{{{W_2}}}{{{M_2}}}}}{{\frac{{{W_2}}}{{{M_2}}} + \frac{{{W_1}}}{{{M_1}}}}}\)…
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