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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

આપેલી પ્રાથમિક રાસાયણીક પ્રક્રિયા,\({A_2} \underset{{{k_{ - 1}}}}{\overset{{{k_1}}}{\longleftrightarrow}} 2A\) માટે \(\frac{{d\left[ A \right]}}{{dt}}\) શું થશે?

  1. A \({k_1}\left[ {{A_2}} \right] - {k_{ - 1}}{\left[ A \right]^2}\)
  2. B \(2{k_1}\left[ {{A_2}} \right] - {k_{ - 1}}{\left[ A \right]^2}\)
  3. C \({k_1}\left[ {{A_2}} \right] + {k_{ - 1}}{\left[ A \right]^2}\)
  4. D \(2{k_1}\left[ {{A_2}} \right] - {2k_{ - 1}}{\left[ A \right]^2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2{k_1}\left[ {{A_2}} \right] - {2k_{ - 1}}{\left[ A \right]^2}\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{2}\frac{{d[A]}}{{dt}}\, = \, - \,{K_1}\,{[A]_2}\, + \,{K_{ - 1}}\,{[A]^2}\) \(\frac{{d[A]}}{{dt}}\, = \,2{K_1}\,{[A]_2}\, - \,2{K_{ - 1}}\,{[A]^2}\)
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