JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For an elementary chemical reaction, \({A_2} \underset{{{k_{ - 1}}}}{\overset{{{k_1}}}{\longleftrightarrow}} 2A\) the expression for \(\frac{{d\left[ A \right]}}{{dt}}\) is
- A \({k_1}\left[ {{A_2}} \right] - {k_{ - 1}}{\left[ A \right]^2}\)
- B \(2{k_1}\left[ {{A_2}} \right] - {k_{ - 1}}{\left[ A \right]^2}\)
- C \({k_1}\left[ {{A_2}} \right] + {k_{ - 1}}{\left[ A \right]^2}\)
- D \(2{k_1}\left[ {{A_2}} \right] - {2k_{ - 1}}{\left[ A \right]^2}\)
Answer & Solution
Correct Answer
(D) \(2{k_1}\left[ {{A_2}} \right] - {2k_{ - 1}}{\left[ A \right]^2}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2}\frac{{d[A]}}{{dt}}\, = \, - \,{K_1}\,{[A]_2}\, + \,{K_{ - 1}}\,{[A]^2}\) \(\frac{{d[A]}}{{dt}}\, = \,2{K_1}\,{[A]_2}\, - \,2{K_{ - 1}}\,{[A]^2}\)
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