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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

આપેલા કોષ માટે \(298\,K\) પર પ્રમાણિત ગિબ્સ મુક્ત ઊર્જા \(kJ\,mol^{-1}\) માં ગણો. \(Zn(s)\, + \,C{u^{2 + }}(aq)\, \to \,Z{n^{2 + }}(aq) + Cu\,(s)\) \((298\,K\) પર \({E^o} = 2\,V,\) ફેરાડે અચળાંક \(F = 96500\, C\, mol^{-1})\)

  1. A \(-192\)
  2. B \(384\)
  3. C \(-384\)
  4. D \(192\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-384\)

Step-by-step Solution

Detailed explanation

\(\Delta G = - 2 \times 96000 \times 2\) \(\Delta G = - nF{E^o}\) \(\Delta G = - 2 \times 96000 \times 2\,J\) \(\Delta G = - 384\,kJ\,mol^{-1}\)
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