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JEE Mains · Chemistry · STD 11 - 2. structure of atom

\(300 nm\) તરંગલંબાઈના વિકિરણવાળા એક મોલ ફોટોનની ઊર્જા \(\dots\dots\dots\)\(kJ\,\,{ mol }{ }^{-1}\) શોધો. (આપેલ : \(h =6.63 \times 10^{-34} \,Js , N _{ A }=6.02 \times 10^{23} \,mol ^{-1}\), \(c =3 \times 10^{8}\, ms ^{-1}\) )

  1. A \(235\)
  2. B \(325\)
  3. C \(399\)
  4. D \(435\)
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Answer & Solution

Correct Answer

(C) \(399\)

Step-by-step Solution

Detailed explanation

Energy of one mole of photons \(=\frac{ hc }{\lambda} \times N _{ A }\) \(\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{300 \times 10^{-9}} \times 6.02 \times 10^{23}\) \(=399.13 \times 10^{3} \,Joule / mole\) \(=399\, kJ / mole\)
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