JEE Mains · Chemistry · STD 11 - 2. structure of atom
The energy of one mole of photons of radiation of wavelength \(300 nm\) is ...... \(kJ \,mol ^{-1}\). (Given : \(h =6.63 \times 10^{-34} \,Js , N _{ A }=6.02 \times 10^{23} \,mol ^{-1}\), \(c =3 \times 10^{8}\, ms ^{-1}\) )
- A \(235\)
- B \(325\)
- C \(399\)
- D \(435\)
Answer & Solution
Correct Answer
(C) \(399\)
Step-by-step Solution
Detailed explanation
Energy of one mole of photons \(=\frac{ hc }{\lambda} \times N _{ A }\) \(\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{300 \times 10^{-9}} \times 6.02 \times 10^{23}\) \(=399.13 \times 10^{3} \,Joule / mole\) \(=399\, kJ / mole\)
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