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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(0.1\,M\,CH _{3} COOH\) ના \(50\,mL\) નું \(0.1\,M\,NaOH\) વિરૂદ્ધ અનુમાપન કરવામાં આવે છે.જ્યારે \(25\, mL\, NaOH\) ને ઉમેરવામાં આવે છે ત્યારે દ્રાવણની \(pH\) \(.......\,\times \,10^{-2}\) થશે. (પૂર્ણાંક જવાબ) (આપેલ : \(\left.pK _{ a }\left( CH _{3} COOH \right)=4.76\right)\) \(\log 2=0.30\) \(\log 3=0.48\) \(\log 5=0.69\) \(\log 7=0.84\) \(\log 11=1.04\)

  1. A \(963\)
  2. B \(123\)
  3. C \(476\)
  4. D \(596\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(476\)

Step-by-step Solution

Detailed explanation

Moles of \(CH _{3} COOH =5\, m\, mole\, moles\) of \(NaOH =2.5\, m\, mole\) \(NaOH + CH _{3} COOH \longrightarrow CH _{3} COONa + H _{2} O\) \(2.5\, m\, mole \quad\quad 2.5 \,m\,mole\) \(0 \quad\quad\quad\quad\quad 2.5 m \text { mole } \quad\quad2.5 m \text { mole }\) so buffer…
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