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GUJCET · Physics · Atoms

5 MeV ઊર્જા ધરાવતો \(\propto\) કણ હેડ-ઓન સંધાત અનુભવે છે, તો Z = 50 પરમાણુક્રમાંક ધરાવતા ન્યુક્લિયસથી તેનું Distance of closest Approach _________ x\(10^{-14}\) હશે.
\(\begin{aligned} & \left(k=9 \times 10^9 \mathrm{SI}, e=1.6 \times 10^{-19} \mathrm{C} 1 \mathrm{eV}=1.6 \times\right. \\ & \left.10^{-19} \mathrm{~J}\right)\end{aligned}\)

  1. A 0.72
  2. B 2.88
  3. C 1.44
  4. D 5.76
Verified Solution

Answer & Solution

Correct Answer

(B) 2.88

Step-by-step Solution

Detailed explanation

B
Distance of closest approach
\(r_0=\frac{k q_1 q_2}{\mathrm{~K}}\)
\(r_0=\frac{9 \times 10^9 \times(2 e)(\mathrm{Ze})}{5 \times 10^6 \times 1.6 \times 10^{-19}}\)
\(r_0=\frac{9 \times 10^9 \times 2 \times 50 \times\left(1.6 \times 10^{-19}\right)^2}{5 \times 10^6 \times 1.6 \times 10^{-19}}\)
\(r_\sigma=2.88 \times 10^{-14} \mathrm{~m}\).
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