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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2021
  • Hard
  • MCQ

What will be the magnitude of electric field at point \(O\) as shown in figure ? Each side of the figure is \(I\) and perpendicular to each other.

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Answer & Solution

Correct Answer

(B) \(\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{(2l^{2})}(2 \sqrt{2}-1)\)

Step-by-step Solution

Detailed explanation

Electric field for point charge

\(E_{1}=\frac{k q}{\ell^{2}}=E_{2}\)

\(E_{3}=\frac{k q}{(\sqrt{2} \ell)^{2}}=\frac{k q}{2 \ell^{2}}\)

\(E=\frac{\sqrt{2} k q}{\ell^{2}}-\frac{k q}{2 \ell^{2}}=\frac{k q}{2 \ell^{2}}(2 \sqrt{2}-1)\)

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