JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Two concentric circular coils with radii \(1\,cm\) and \(1000\,cm\), and number of turns \(10\) and \(200\) respectively are placed coaxially with centers coinciding. The mutual inductance of this arrangement will be \(.........\times 10^{-8}\,H\)(Take, \(\pi^2=10\))
- A \(3\)
- B \(2\)
- C \(4\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
\(r_1=1\,cm , N_1=10\) \(r_2=1000\,cm , N_2=200\) \(\phi_{1.2}=M I_2\) \(N_2 \vec{B}_2 \cdot N_1 \vec{A}_1=M I_2\) \(\Rightarrow N_1 N_2 \frac{\mu_0 I_2}{2 r_2} \cdot \pi r_1^2=M I_2\)…
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