JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A proton, a deuteron and an \(\alpha\) particle are moving with same momentum in a uniform magnetic field. The ratio of magnetic forces acting on them is.......... and their speed is.................. in the ratio.
- A \(1: 2: 4\) and \(2: 1: 1\)
- B \(2: 1: 1\) and \(4: 2: 1\)
- C \(4: 2: 1\) and \(2: 1: 1\)
- D \(1: 2: 4\) and \(1: 1: 2\)
Answer & Solution
Correct Answer
(B) \(2: 1: 1\) and \(4: 2: 1\)
Step-by-step Solution
Detailed explanation
\(F=q(\vec{v} \times \vec{B})=\frac{q}{m}(\vec{P} \times \vec{B})\) \(\Rightarrow F \propto \frac{ q }{ m }\) thus \(F _{1}: F _{2}: F _{3}=\frac{ q _{1}}{ m _{1}}: \frac{ q _{2}}{ m _{2}}: \frac{ q _{3}}{ m _{3}}\)…
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