JEE Mains · Physics · STD 12 -7. Alternating current
An ac current is represented as
\(\mathrm{i}=5 \sqrt{2}+10 \cos \left(650 \pi \mathrm{t}+\frac{\pi}{6}\right) \mathrm{Amp}\)
The r.m.s value of the current is
- A 50 Amp
- B 100 Amp
- C 10 Amp
- D \(5 \sqrt{2} \mathrm{Amp}\)
Answer & Solution
Correct Answer
(C) 10 Amp
Step-by-step Solution
Detailed explanation
\(i=5 \sqrt{2}+10 \cos \left(650 \pi t+\frac{\pi}{6}\right)\) \(\mathrm{i}^2=50+100 \cos ^2\left(650 \pi \mathrm{t}+\frac{\pi}{6}\right)\) \(+(2)(5 \sqrt{2})(10) \cos \left(650 \pi t+\frac{\pi}{6}\right)\) \(\left\langle\mathrm{i}^2\right\rangle=50+\frac{100}{2}+0\)…
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