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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2025
  • Easy
  • MCQ

An ac current is represented as
\(\mathrm{i}=5 \sqrt{2}+10 \cos \left(650 \pi \mathrm{t}+\frac{\pi}{6}\right) \mathrm{Amp}\)
The r.m.s value of the current is

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Answer & Solution

Correct Answer

(C) 10 Amp

Step-by-step Solution

Detailed explanation

\(i=5 \sqrt{2}+10 \cos \left(650 \pi t+\frac{\pi}{6}\right)\)
\(\mathrm{i}^2=50+100 \cos ^2\left(650 \pi \mathrm{t}+\frac{\pi}{6}\right)\)
\(+(2)(5 \sqrt{2})(10) \cos \left(650 \pi t+\frac{\pi}{6}\right)\)
\(\left\langle\mathrm{i}^2\right\rangle=50+\frac{100}{2}+0\)
\(\left. \lt \mathrm{i}^2\right\rangle=100\)
\( \lt \mathrm{i} \gt =10 \mathrm{Amp}\)
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