JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2021
- Medium
- Numerical
The position of the centre of mass of a uniform semi-circular wire of radius \('R'\) placed in \(x-y\) plane with its centre at the origin and the line joining its ends as \(x\)-axis is given by \(\left(0, \frac{x R}{\pi}\right)\). Then, the value of \(|x|\) is ...... .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(COM\) of semi-circular ring is at \(\frac{2 R}{\pi}\)
Distance from centre \(\Rightarrow x=2\)
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