JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Two charges \(\mathrm{q}_1\) and \(\mathrm{q}_2\) are separated by a distance of 30 cm. A third charge \(q_3\) initially at ' C ' as shown in the figure, is moved along the circular path of radius 40 cm from C to D. If the difference in potential energy due to movement of \(q_3\) from \(C\) to \(D\) is given by \(\frac{\mathrm{q}_3 \mathrm{~K}}{4 \pi \epsilon_0}\), the value of K is :
- A \(8 \mathrm{q}_2\)
- B \(6 \mathrm{q}_2\)
- C \(8 q_1\)
- D \(6 \mathrm{q}_1\)
Answer & Solution
Correct Answer
(A) \(8 \mathrm{q}_2\)
Step-by-step Solution
Detailed explanation
Potential at C \(\mathrm{V}_{\mathrm{C}}=\frac{\mathrm{kq}_1}{0.4}+\frac{\mathrm{kq}_2}{0.5}\) Potential at D \(\mathrm{V}_{\mathrm{D}}=\frac{\mathrm{kq}_1}{0.4}+\frac{\mathrm{kq}_2}{0.1}\)…
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