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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2020
- Medium
- Numerical
The magnifying power of a telescope with tube \(60\; \mathrm{cm}\) is \(5 .\) What is the focal length of its eye piece?......\(cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(\mathrm{L}=\mathrm{f}_{0}+\mathrm{f}_{\mathrm{e}}=60\; \mathrm{cm}\)
\(\mathrm{M}=\frac{\mathrm{f}_{0}}{\mathrm{f}_{\mathrm{e}}}=5\)
\(\Rightarrow \mathrm{f}_{0}=5 \mathrm{f}_{\mathrm{e}}\)
\(\therefore \quad 6 \mathrm{f}_{\mathrm{e}}=60 \mathrm{cm}\)
\(\mathrm{f}_{\mathrm{e}}=10 \mathrm{cm}\)
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