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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2020
  • Medium
  • Numerical

The magnifying power of a telescope with tube \(60\; \mathrm{cm}\) is \(5 .\) What is the focal length of its eye piece?......\(cm\)

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Answer & Solution

Correct Answer

(D) \(10\)

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Detailed explanation

\(\mathrm{L}=\mathrm{f}_{0}+\mathrm{f}_{\mathrm{e}}=60\; \mathrm{cm}\)

\(\mathrm{M}=\frac{\mathrm{f}_{0}}{\mathrm{f}_{\mathrm{e}}}=5\)

\(\Rightarrow \mathrm{f}_{0}=5 \mathrm{f}_{\mathrm{e}}\)

\(\therefore \quad 6 \mathrm{f}_{\mathrm{e}}=60 \mathrm{cm}\)

\(\mathrm{f}_{\mathrm{e}}=10 \mathrm{cm}\)

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