JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Two charges \(7 \mu \mathrm{c}\) and \(-4 \mu \mathrm{c}\) are placed at \((-7 \mathrm{~cm}, 0,0)\) and \((7 \mathrm{~cm}, 0,0)\) respectively. Given, \(\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}\), the electrostatic potential energy of the charge configuration is :
- A -1.8 J
- B -2.0 J
- C -1.5 J
- D -1.2 J
Answer & Solution
Correct Answer
(A) -1.8 J
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P.E. of two charges…
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