JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2025
- Medium
- MCQ
Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is \(V\). The potential difference between the points A and B (shown in the figure) is :

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\frac{2}{5} \mathrm{~V}\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & \text { Using } \Delta V=E(\Delta d) \\ & V=E(10) \\ & V_{A B}=E \cdot 4=\frac{V}{10} \times 4=\frac{2 V}{5}\end{aligned}\)
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