ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2025
  • Medium
  • MCQ

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is \(V\). The potential difference between the points A and B (shown in the figure) is :

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2}{5} \mathrm{~V}\)

Step-by-step Solution

Detailed explanation


\(\begin{aligned} & \text { Using } \Delta V=E(\Delta d) \\ & V=E(10) \\ & V_{A B}=E \cdot 4=\frac{V}{10} \times 4=\frac{2 V}{5}\end{aligned}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app