JEE Mains · Physics · STD 11 - 10.2 transmission of heat
A rod \(C D\) of thermal resistance \(10.0\; {KW}^{-1}\) is joined at the middle of an identical rod \({AB}\) as shown in figure, The end \(A, B\) and \(D\) are maintained at \(200^{\circ} {C}, 100^{\circ} {C}\) and \(125^{\circ} {C}\) respectively. The heat current in \({CD}\) is \({P}\) watt. The value of \({P}\) is ... .
- A \(2\)
- B \(3\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Rods are identical so \({R}_{{AB}}={R}_{{CD}}=10 {Kw}^{-1}\) \({C}\) is mid-point of \({AB}\), so \({R}_{{AC}}={R}_{{CB}}=5 {K} {w}^{-1}\) at point \({C}\) \(\frac{200-{T}}{5}=\frac{{T}-125}{10}+\frac{{T}-100}{5}\) \(2(200-{T})={T}-125+2({T}-100)\)…
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