JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A galvanometer having coil resistance \(10 \ \Omega\) shows a full scale deflection for a current of \(3 \mathrm{~mA}\). For it to measure a current of \(8 \mathrm{~A}\), the value of the shunt should be:
- A \(3 \times 10^{-3}\ \Omega\)
- B \(4.85 \times 10^{-3} \ \Omega\)
- C \(3.75 \times 10^{-3} \ \Omega\)
- D \(2.75 \times 10^{-3} \ \Omega\)
Answer & Solution
Correct Answer
(C) \(3.75 \times 10^{-3} \ \Omega\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{G}=10\ \Omega\) \( \mathrm{I}_{\mathrm{g}}=3 \mathrm{~mA} \) \( \mathrm{I}=8 \mathrm{~A}\) In case of conversion of galvanometer into ammeter. We have \(\mathrm{I}_{\mathrm{g}} \mathrm{G}=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \mathrm{S}\)…
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