JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2024
- Hard
- MCQ
A galvanometer having coil resistance \(10 \ \Omega\) shows a full scale deflection for a current of \(3 \mathrm{~mA}\). For it to measure a current of \(8 \mathrm{~A}\), the value of the shunt should be:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(3.75 \times 10^{-3} \ \Omega\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{G}=10\ \Omega\)
\( \mathrm{I}_{\mathrm{g}}=3 \mathrm{~mA} \)
\( \mathrm{I}=8 \mathrm{~A}\)
In case of conversion of galvanometer into ammeter.
We have \(\mathrm{I}_{\mathrm{g}} \mathrm{G}=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \mathrm{S}\)
\( S=\frac{I_g G}{I-I_g} \)
\( S=\frac{\left(3 \times 10^{-3}\right) 10}{8-0.003}=3.75 \times 10^{-5} \Omega\)
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