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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
A moving proton and electron have the same deBroglie wavelength. If \({K}\) and \({P}\) denote the \({KE}\). and momentum respectively. Then choose the correct option :
- A \({K}_{{p}}<{K}_{{q}}\) and \({P}_{{p}}={P}_{{e}}\)
- B \({K}_{{p}}={K}_{{q}}\) and \({P}_{{p}}={P}_{{e}}\)
- C \({K}_{{p}}<{K}_{{q}}\) and \({P}_{{p}}<{P}_{{e}}\)
- D \({K}_{{p}}>{K}_{{a}}\) and \({P}_{{p}}={P}_{{e}}\)
Answer & Solution
Correct Answer
(A) \({K}_{{p}}<{K}_{{q}}\) and \({P}_{{p}}={P}_{{e}}\)
Step-by-step Solution
Detailed explanation
\(\lambda_{{p}}=\frac{{h}}{{P}_{{p}}} \quad \lambda_{{e}}=\frac{{h}}{{P}_{{e}}}\) \(\because \lambda_{{p}}=\lambda_{{e}}\) \(\Rightarrow {P}_{{p}}={P}_{{e}}\) \(({K})_{{p}}=\frac{{P}_{{p}}^{2}}{2 {m}_{{p}}}\) \(({K})_{{e}}=\frac{{P}_{{e}}^{2}}{2 {m}_{{e}}}\)…
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