A plane polarized monochromatic \(EM\) wave is travelling a vacuum along \(z\) direction such that at \(t\, = t_1\) it is found that the electric field is zero at a spatial point \(z_1\) . The next zero that occurs in its neighbourhood is at \(z_2\). The frequency of the electromagnetic wave is:

A \(\frac{{3 \times {{10}^8}}}{{\left| {{z_2} - {z_1}} \right|}}\)
B \(\frac{{6 \times {{10}^8}}}{{\left| {{z_2} - {z_1}} \right|}}\)
C \(\frac{{1.5 \times {{10}^8}}}{{\left| {{z_2} - {z_1}} \right|}}\)
D \(\frac{1}{{{t_1} + \frac{{\left| {{z_{2 - }}{z_1}} \right|}}{{3 \times {{10}^8}}}}}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{{3 \times {{10}^8}}}{{\left| {{z_2} - {z_1}} \right|}}\)

Step-by-step Solution

Detailed explanation

Using \(E=E_{0}-e^{j(k z-\omega t)}\) Given, at \(t=t_{1}, z=z_{1}, E=0\) the next zero that occurs in it's neighborhood is at \(z_{2},\) the frequency of the electromagnetic wave at \(t_{2}\) \(e^{i\left(k z_{1}-\omega t_{1}\right)}=e^{i\left(k z_{2}-\omega x_{2}\right)}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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