JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
Two bodies of masses \(m_{1}=5\,kg\) and \(m _{2}=3\,kg\) are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass \(m _{1}\) will be\(....N\) [Take \(g=10\,ms ^{-2}\) ]
- A \(30\)
- B \(40\)
- C \(50\)
- D \(60\)
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
For equilibrium \(m_{2} g=m_{1} g \sin \theta\) \(\sin \theta=\frac{m_{2}}{m_{1}}=\frac{3}{5}\) \(\cos \theta=\frac{4}{5}\) Normal force on \(m _{1}=5\,g \cos \theta\) \(=5 \times 10 \times \frac{4}{5}=40\,N\)
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