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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2022
  • Hard
  • Numerical

Two bodies of masses \(m_{1}=5\,kg\) and \(m _{2}=3\,kg\) are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass \(m _{1}\) will be\(....N\) [Take \(g=10\,ms ^{-2}\) ]

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Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

For equilibrium \(m_{2} g=m_{1} g \sin \theta\)

\(\sin \theta=\frac{m_{2}}{m_{1}}=\frac{3}{5}\)

\(\cos \theta=\frac{4}{5}\)

Normal force on \(m _{1}=5\,g \cos \theta\)

\(=5 \times 10 \times \frac{4}{5}=40\,N\)

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