ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2021
  • Hard
  • Numerical

A monoatomic gas of mass \(4.0\, u\) is kept in an insulated container. Container is moving with velocity \(30 \,m / s\). If container is suddenly stopped then change in temperature of the gas \(\left( R =\right.\) gas constant) is \(\frac{ x }{3 R } .\) Value of \(x\) is ..........

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(3600\)

Step-by-step Solution

Detailed explanation

Given that mass of gas is \(4 u\) hence its molar

mass \(M\) is \(4 g / mol\)

\(\therefore \frac{1}{2} mv ^{2}= n C _{ v } \Delta T\)

\(\frac{1}{2} m \times(30)^{2}=\frac{ m }{ M } \times \frac{3 R }{2} \times \Delta T\)

\(\therefore \Delta T =\frac{3600}{3 R }\)

Same subject
Explore more questions on app