JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The \(V-I\) characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is
- A \(10\)
- B \(10^{-6}\)
- C \(10^6\)
- D \(100\)
Answer & Solution
Correct Answer
(B) \(10^{-6}\)
Step-by-step Solution
Detailed explanation
Forward bias resistance \(=\frac{\Delta V}{\Delta I}=\frac{0.1}{10 \times 10^{-3}}=10 \Omega\) Reverse bias resistance \(=\frac{10}{10^{-6}}=10^{7} \Omega\) Ratio of resistances \(=\,\frac {Forward \,\,bias\,\, resistance }{Reverse\,\, bias \,\,resistance}\) \(=10^{-6}\)
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