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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The radiation corresponding to \(3 \rightarrow 2\) transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of \(5 \times 10^{-4} \,{T}\). Assume that the radius of the largest circular path followed by these electrons is \(7\, {mm}\), the work function of the metal is \(.....\,{eV}\) (Mass of electron \(=9.1 \times 10^{-31} \,{kg}\) )
- A \(0.82\)
- B \(0.16\)
- C \(1.88\)
- D \(1.36\)
Answer & Solution
Correct Answer
(A) \(0.82\)
Step-by-step Solution
Detailed explanation
\(1.51 \longrightarrow {N}=3\) \(3.4 \longrightarrow {N}=2\) \(13.6 \longrightarrow {N}=1\) \(3 \rightarrow 2 \Rightarrow 1.89\, {eV}\) \(5 \times 10^{-4}\, {T}\) \({r}=7 \,{mm}\) \(r=\frac{m v}{q B} \Rightarrow m v=q r B\)…
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