JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
What is the conductivity of a semiconductor sample having electron concentration of \(5 \times 10^{18}\, m^{-3}\), hole concentration of \(5 \times 10^{19}\, m^{-3}\), electron mobility of \(2 .0\, m^2\, v^{-1}\, s^{-1}\) and hole mobility of \(0.01\, m^2\, v^{ -1}\, s^{-1}\) ?........\({\left( {\Omega - m} \right)^{ - 1}}\) (Take charge of electron as \(1.6 \times 10^{-19}\, C\))
- A \(1.68\)
- B \(1.83\)
- C \(0.59\)
- D \(1.20\)
Answer & Solution
Correct Answer
(A) \(1.68\)
Step-by-step Solution
Detailed explanation
The conductivity of semiconductor \( \sigma =\mathrm{e}\left(\mathrm{n}_{\mathrm{e}} \mu_{\mathrm{e}}+\mathrm{n}_{\mathrm{h}} \mu_{\mathrm{h}}\right)\) \(=1.6 \times 10^{-19}\left(5 \times 10^{18} \times 2+5 \times 10^{19} \times 0.01\right) \)…
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