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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

An electric dipole of mass m, charge q, and length \(l\) is placed in a uniform electric field \(\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \hat{i}\). When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be:

  1. A \(\frac{1}{2 \pi} \sqrt{\frac{m l}{2 q E_0}}\)
  2. B \(2 \pi \sqrt{\frac{\mathrm{~m} l}{\mathrm{qE}_0}}\)
  3. C \(\frac{1}{2 \pi} \sqrt{\frac{2 \mathrm{~m} l}{\mathrm{qE}_0}}\)
  4. D \(2 \pi \sqrt{\frac{\mathrm{~m} l}{2 \mathrm{qE}_0}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \pi \sqrt{\frac{\mathrm{~m} l}{2 \mathrm{qE}_0}}\)

Step-by-step Solution

Detailed explanation

\(\tau=P E_0 \sin \theta\) If \(\theta\) is small…
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