JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The dimensions of \(\left(\frac{ B ^{2}}{\mu_{0}}\right)\) will be. (if \(\mu_{0}\) : permeability of free space and \(B\) : magnetic field)
- A \(\left[ ML ^{2} T ^{-2}\right]\)
- B \(\left[ ML T ^{-2}\right]\)
- C \(\left[ ML ^{-1} T ^{-2}\right]\)
- D \(\left[ ML ^{2} T ^{-2} A ^{-1}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[ ML ^{-1} T ^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(u =\frac{ B ^{2}}{2 \mu_{0}}\) \(u \rightarrow\) Energy per unit volume \(\left[\frac{ B ^{2}}{\mu_{0}}\right]=[ u ]=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ L ^{3}\right]}=\left[ ML ^{-1} T ^{-2}\right]\)
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