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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Medium
  • MCQ

The dimensions of \(\left(\frac{ B ^{2}}{\mu_{0}}\right)\) will be. (if \(\mu_{0}\) : permeability of free space and \(B\) : magnetic field)

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Answer & Solution

Correct Answer

(C) \(\left[ ML ^{-1} T ^{-2}\right]\)

Step-by-step Solution

Detailed explanation

\(u =\frac{ B ^{2}}{2 \mu_{0}}\)

\(u \rightarrow\) Energy per unit volume

\(\left[\frac{ B ^{2}}{\mu_{0}}\right]=[ u ]=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ L ^{3}\right]}=\left[ ML ^{-1} T ^{-2}\right]\)

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