JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The transfer characteristic curve of a transistor, having input and output resistance \(100\,\Omega \) and \(100\,k\Omega \) respectively, is shown in the figure. The Voltage and Power gain, are respectively
- A \(5 \times {10^4}\,,\,2.5 \times {10^6}\)
- B \(5 \times {10^4}\,,\,5 \times {10^6}\)
- C \(5 \times {10^4}\,,\,5 \times {10^5}\)
- D \(2.5 \times {10^4}\,,\,2.5 \times {10^6}\)
Answer & Solution
Correct Answer
(A) \(5 \times {10^4}\,,\,2.5 \times {10^6}\)
Step-by-step Solution
Detailed explanation
\({V_{\text {gain }}=\left(\frac{\Delta I_{C}}{\Delta I_{B}}\right) \frac{R_{\text {out }}}{R_{\text {in }}}=\left(\frac{5 \times 10^{-3}}{100 \times 10^{-6}}\right) \times 10^{3}}\) \(=\frac{1}{20} \times 10^{8}=5 \times 10^{4} \)…
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