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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2019
  • Hard
  • MCQ

The transfer characteristic curve of a transistor, having input and output resistance \(100\,\Omega \) and \(100\,k\Omega \) respectively, is shown in the figure. The Voltage and Power gain, are respectively

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Answer & Solution

Correct Answer

(A) \(5 \times {10^4}\,,\,2.5 \times {10^6}\)

Step-by-step Solution

Detailed explanation

\({V_{\text {gain }}=\left(\frac{\Delta  I_{C}}{\Delta I_{B}}\right) \frac{R_{\text {out }}}{R_{\text {in }}}=\left(\frac{5 \times 10^{-3}}{100 \times 10^{-6}}\right) \times 10^{3}}\)

\(=\frac{1}{20}  \times 10^{8}=5 \times 10^{4} \)

\(P_{\text {gain }} =\left(\frac{\Delta I_{C}}{\Delta I_{b}}\right)\left(V_{\text {gain }}\right) \)

\(=\left(\frac{5 \times 10^{-3}}{100 \times 10^{-6}}\right)\left(5 \times 10^{4}\right)\)

\(=2.5 \times 10^{6}\)

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