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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2023
  • Medium
  • Numerical

An \(emf\) of \(0.08\,V\) is induced in a metal rod of length \(10\,cm\) held normal to a uniform magnetic field of \(0.4\,T\), when moves with a velocity of ...........\(ms^{-1}\)

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Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

Induced emf \(= Blv\)

\(\Rightarrow 0.08=0.4\left(\frac{10}{100}\right) v\)

\(\Rightarrow v =\left(\frac{0.08 \times 10}{0.4}\right) \quad \Rightarrow v =2\,m / s\)

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