JEE Mains · Physics · STD 12 -6. Electromagnetic induction
An \(emf\) of \(0.08\,V\) is induced in a metal rod of length \(10\,cm\) held normal to a uniform magnetic field of \(0.4\,T\), when moves with a velocity of ...........\(ms^{-1}\)
- A \(2\)
- B \(3.2\)
- C \(0.5\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Induced emf \(= Blv\) \(\Rightarrow 0.08=0.4\left(\frac{10}{100}\right) v\) \(\Rightarrow v =\left(\frac{0.08 \times 10}{0.4}\right) \quad \Rightarrow v =2\,m / s\)
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