JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2023
- Medium
- Numerical
An \(emf\) of \(0.08\,V\) is induced in a metal rod of length \(10\,cm\) held normal to a uniform magnetic field of \(0.4\,T\), when moves with a velocity of ...........\(ms^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Induced emf \(= Blv\)
\(\Rightarrow 0.08=0.4\left(\frac{10}{100}\right) v\)
\(\Rightarrow v =\left(\frac{0.08 \times 10}{0.4}\right) \quad \Rightarrow v =2\,m / s\)
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