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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about \(150\, N/C\), directed inward towards the center of the Earth . This gives the total net surface charge carried by the Earth to be......\(kC\) [Given \({\varepsilon _0} = 8.85 \times {10^{ - 12}}\,{C^2}/N - {m^2},{R_E} = 6.37 \times {10^6}\,m\)]

  1. A \( + 670\)
  2. B \( - 670\)
  3. C \( - 680\)
  4. D \( + 680\)
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Answer & Solution

Correct Answer

(C) \( - 680\)

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Detailed explanation

Given, Electric field \(\mathrm{E}=150\, \mathrm{N} / \mathrm{C}\) Total surface charge carried by earth \(q=?\) According to Gauss's law. \(\phi=\frac{q}{\epsilon_{0}}=E A\) \( \text { or, } q=\epsilon_{0} \mathrm{EA}\) \(=\epsilon_{0} \mathrm{E} \pi r^{2} \)…
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