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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2022
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  • MCQ

The oscillating magnetic field in a plane electromagnetic wave is given by \(B _{ y }=5 \times 10^{-6} \sin\) \(1000\,\pi\left(5 x -4 \times 10^{8} t \right) T\). The amplitude of electric field will be.

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Answer & Solution

Correct Answer

(D) \(4 \times 10^{2} \,Vm ^{-1}\)

Step-by-step Solution

Detailed explanation

\(B _{0}=5 \times 10^{-6}\)

\(v =\) Speed of wave \(=\frac{4 \times 10^{8}}{5}=8 \times 10^{7}\left[\therefore v =\frac{ w }{ k }\right]\)

\(E _{0}= vB B _{0}=40 \times 10^{1}\)

\(=4 \times 10^{2} V / m\)

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