JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2017
- Medium
- Numerical
A copper ball of mass \(100\ gm\) is at a temperature \(T\). It is dropped in a copper calorimeter of mass \(100\ gm\), filled with \(170\ gm\) of water at room temperature. Subsequently, the temperature of the system is found to be \(75^o C\). \(T\) is given by......\(^oC\) (Given : room temperature \(= 30^o C\), specific heat of copper \(=\) \(0.1\) \(cal/gm^o C\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(885\)
Step-by-step Solution
Detailed explanation
\(Heat\,lost\,by\,copper\,ball=heat\,gained\,by\,copper\,calorimeter\,and\,water.\)
\(\therefore m{s_{Cu}}\left( {T - {T_f}} \right) = {m_{Cu}} \times {s_{Cu}}\left( {{T_f} - {T_0}} \right) + \)
\({m_w}{s_w}\left( {{T_f} - {T_0}} \right)\)
\(or\,100 \times 0.1 \times \left[ {T - 75} \right] = 100 \times 0.1\left( {75 - 30} \right) + \)
\(170 \times 1\left( {75 - 30} \right)\)
\(10T - 750 = 450 + 750\)
\(10T = 750 + 450 + 7650 = 8850\)
\(T = {885^ \circ }C\)
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