JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2019
- Hard
- MCQ
Shown in the figure is a shell made of a conductor. It has inner radius \(a\) and outer radius \(b\), and carries charge \(Q\). At its centre is a dipole \(\vec P\) as shown. In this case
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) Electric field outside the shell is the same as that of a point charge at the centre of the shell
Step-by-step Solution
Detailed explanation
Total charge of dipole \(=0,\) so charge induced on outside surface \(=0\).
But due to non uniform electric field of dipole, the charge induced on inner surface is non zero and non uniform.
So, for any observer outside the shell, the resultant electric field is due to Q uniformly distributed on outer surface only and it is equal to.
\(\boxed{E = \frac{{KQ}}{{{r^2}}}}\)
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