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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

Shown in the figure is a shell made of a conductor. It has inner radius \(a\) and outer radius \(b\), and carries charge \(Q\). At its centre is a dipole  \(\vec P\) as shown. In this case

  1. A Surface charge density on the inner surface of the shell is zero everywhere
  2. B Electric field outside the shell is the same as that of a point charge at the centre of the shell
  3. C Surface charge density on the inner surface is uniform and equal to \(\frac{{\left( {Q/2} \right)}}{{4\pi {a^2}}}\)
  4. D Surface charge density on the outer surface depends on \(\left| {\vec P} \right|\)
Verified Solution

Answer & Solution

Correct Answer

(B) Electric field outside the shell is the same as that of a point charge at the centre of the shell

Step-by-step Solution

Detailed explanation

Total charge of dipole \(=0,\) so charge induced on outside surface \(=0\). But due to non uniform electric field of dipole, the charge induced on inner surface is non zero and non uniform. So, for any observer outside the shell, the resultant electric field is due to Q…
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