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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
A particle \(A\) of mass \(‘m’\) and charge \(‘q’\) is accelerated by a potential difference of \(50\, V\). Another particle \(B\) of mass \(‘4\, m’\) and charge \(‘q’\) is accelerated by a potential difference of \(2500\, V\). The ratio of de-Broglie wavelength \(\frac{{{\lambda _A}}}{{{\lambda _B}}}\) is close to
- A \(10.00\)
- B \(0.07\)
- C \(14.14\)
- D \(4.47\)
Answer & Solution
Correct Answer
(C) \(14.14\)
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{{\text{h}}}{{\sqrt {2{\text{mqV}}} }}\) \(\frac{{{\lambda _P}}}{{{\lambda _\alpha }}} = \sqrt {\frac{{4 \times 1 \times 2500}}{{1 \times 1 \times 50}}} \) \( = 10\sqrt 2 = 14.14\)
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