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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2014
  • Medium
  • Numerical

A transverse wave is represented by  \(y = \frac{{10}}{\pi }\,\sin \,\left( {\frac{{2\pi }}{T}t - \frac{{2\pi }}{\lambda }x} \right)\) For what value of the wavelength the wave velocity is twice the maximum particle velocity ..... \(cm\) ?

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Answer & Solution

Correct Answer

(A) \(40\)

Step-by-step Solution

Detailed explanation

Given, amplitude \(a\) \(=10 \mathrm{cm}\)

wave velocity \(=2 \times\) maximum particle velocity

i.e, \(\frac{{\omega \lambda }}{{2\pi }} = 2\frac{{{\rm{a}}\omega }}{\pi }\)

or, \(\quad \lambda=4 \mathrm{a}=4 \times 10=40 \mathrm{cm}\)

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