JEE Mains · Physics · STD 11 - 14. waves and sound
A transverse wave is represented by \(y = \frac{{10}}{\pi }\,\sin \,\left( {\frac{{2\pi }}{T}t - \frac{{2\pi }}{\lambda }x} \right)\) For what value of the wavelength the wave velocity is twice the maximum particle velocity ..... \(cm\) ?
- A \(40\)
- B \(20\)
- C \(10\)
- D \(60\)
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
Given, amplitude \(a\) \(=10 \mathrm{cm}\) wave velocity \(=2 \times\) maximum particle velocity i.e, \(\frac{{\omega \lambda }}{{2\pi }} = 2\frac{{{\rm{a}}\omega }}{\pi }\) or, \(\quad \lambda=4 \mathrm{a}=4 \times 10=40 \mathrm{cm}\)
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