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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2020
  • Medium
  • MCQ

A clock has a continuously moving second's hand of \(0.1\, m\) length. The average acceleration of the tip of the hand (in units of \(ms ^{-2}\) ) is of the order of

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Answer & Solution

Correct Answer

(A) \(10^{-3}\)

Step-by-step Solution

Detailed explanation

\(R=0.1 m\)

\(\omega=\frac{2 \pi}{ T }=\frac{2 \pi}{60}=0.105 rad / sec\)

\(a =\omega^{2} R\)

\(=(0.105)^{2}(0.1)\)

\(=0.0011\)

\(=1.1 \times 10^{-3}\)

Average acceleration is of the order of \(10^{-3}\)

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