JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2020
- Medium
- MCQ
A clock has a continuously moving second's hand of \(0.1\, m\) length. The average acceleration of the tip of the hand (in units of \(ms ^{-2}\) ) is of the order of
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(10^{-3}\)
Step-by-step Solution
Detailed explanation
\(R=0.1 m\)
\(\omega=\frac{2 \pi}{ T }=\frac{2 \pi}{60}=0.105 rad / sec\)
\(a =\omega^{2} R\)
\(=(0.105)^{2}(0.1)\)
\(=0.0011\)
\(=1.1 \times 10^{-3}\)
Average acceleration is of the order of \(10^{-3}\)
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