JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A cube of metal is subjected to a hydrostatic pressure of \(4\;GPa.\) The percentage change in the length of the side of the cube is close to.......\(\%\)
(Given bulk modulus of metal, \(B =8 \times 10^{10}\, Pa\) )
- A \(0.6\)
- B \(1.67\)
- C \(5\)
- D \(20\)
Answer & Solution
Correct Answer
(B) \(1.67\)
Step-by-step Solution
Detailed explanation
\(B =-\frac{\Delta P }{\frac{\Delta V }{ V }}\) \(\left|\frac{\Delta V }{ V }\right|=\frac{\Delta P }{ B }\) \(=\frac{4 \times 10^{9}}{8 \times 10^{10}}=\frac{1}{20}\) \(\frac{\Delta \ell}{\ell}=\frac{1}{3} \times \frac{\Delta V }{ V }=\frac{1}{60}\) Percentage change…
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