JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2020
- Medium
- MCQ
A cube of metal is subjected to a hydrostatic pressure of \(4\;GPa.\) The percentage change in the length of the side of the cube is close to.......\(\%\)
(Given bulk modulus of metal, \(B =8 \times 10^{10}\, Pa\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1.67\)
Step-by-step Solution
Detailed explanation
\(B =-\frac{\Delta P }{\frac{\Delta V }{ V }}\)
\(\left|\frac{\Delta V }{ V }\right|=\frac{\Delta P }{ B }\)
\(=\frac{4 \times 10^{9}}{8 \times 10^{10}}=\frac{1}{20}\)
\(\frac{\Delta \ell}{\ell}=\frac{1}{3} \times \frac{\Delta V }{ V }=\frac{1}{60}\)
Percentage change \(=\frac{\Delta \ell}{\ell} \times 100 \%\)
\(=\frac{100}{60} \%=1.67 \%\)
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