ExamBro
ExamBro
JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2020
  • Medium
  • MCQ

A cube of metal is subjected to a hydrostatic pressure of \(4\;GPa.\) The percentage change in the length of the side of the cube is close to.......\(\%\)
(Given bulk modulus of metal, \(B =8 \times 10^{10}\, Pa\) )

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(1.67\)

Step-by-step Solution

Detailed explanation

\(B =-\frac{\Delta P }{\frac{\Delta V }{ V }}\)

\(\left|\frac{\Delta V }{ V }\right|=\frac{\Delta P }{ B }\)

\(=\frac{4 \times 10^{9}}{8 \times 10^{10}}=\frac{1}{20}\)

\(\frac{\Delta \ell}{\ell}=\frac{1}{3} \times \frac{\Delta V }{ V }=\frac{1}{60}\)

Percentage change \(=\frac{\Delta \ell}{\ell} \times 100 \%\)

\(=\frac{100}{60} \%=1.67 \%\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app