JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2017
- Medium
- MCQ
The following observations were taken for determining surface tension \(T\) of water by capillary method: diameter of capillary, \(D= 1.25 \times 10^{-2}\; m\) rise of water, \(h=1.45 \times 10^{-2}\; m \) Using \(g= 9.80 \;m/s^2\) and the simplified relation \(T = \frac{{rhg}}{2}\times 10^3 N/m\) , the possible error in surface tension is ........... \(\%\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1.5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}=\frac{\mathrm{rhg}}{2} \times 10^{3} \mathrm{N} / \mathrm{m}\)
\(\frac{\Delta \mathrm{T}}{\mathrm{T}}=\left|\frac{\Delta \mathrm{r}}{\mathrm{r}}\right|+\left|\frac{\Delta \mathrm{h}}{\mathrm{h}}\right|=\frac{0.01}{1.25}+\frac{0.01}{1.45}\)
\(\%\) error \(=\frac{\Delta \mathrm{T}}{\mathrm{T}} \times 100=\frac{1}{1.25}+\frac{1}{1.45}=0.8+0.69=1.5 \%\)
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