JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The following observations were taken for determining surface tension \(T\) of water by capillary method: diameter of capillary, \(D= 1.25 \times 10^{-2}\; m\) rise of water, \(h=1.45 \times 10^{-2}\; m \) Using \(g= 9.80 \;m/s^2\) and the simplified relation \(T = \frac{{rhg}}{2}\times 10^3 N/m\) , the possible error in surface tension is ........... \(\%\)
- A \(0.15 \)
- B \(1.5\)
- C \(2.4\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(1.5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}=\frac{\mathrm{rhg}}{2} \times 10^{3} \mathrm{N} / \mathrm{m}\) \(\frac{\Delta \mathrm{T}}{\mathrm{T}}=\left|\frac{\Delta \mathrm{r}}{\mathrm{r}}\right|+\left|\frac{\Delta \mathrm{h}}{\mathrm{h}}\right|=\frac{0.01}{1.25}+\frac{0.01}{1.45}\) \(\%\) error…
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