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JEE Mains · Physics · STD 11 - 11. thermodynamics
Match List \(I\) with List \(II\) :
| List \(I\) | List \(II\) |
| \(A\) Isothermal Process | \(I\) Work done by the gas decreases internal energy |
| \(B\) Adiabatic Process | \(II\) No change in internal energy |
| \(C\) Isochoric Process | \(III\) The heat absorbed goes partly to increase internal energy and partly to do work |
| \(D\) Isobaric Process | \(IV\) No work is done on or by the gas |
- A \(A-II, B-I, C-III, D-IV\)
- B \(A-II, B-I, C-IV, D-III\)
- C \(A-I, B-II, C-IV, D-III\)
- D \(A-I, B-II, C-III, D-IV\)
Answer & Solution
Correct Answer
(B) \(A-II, B-I, C-IV, D-III\)
Step-by-step Solution
Detailed explanation
\(\Delta U = nC _{ v } \Delta T\) For isothermal process \(T\) is constant So \(\Delta U =0\) \(A \longrightarrow II\) Adiabatic process \(\Delta Q =0\) \(\Delta Q =\Delta U +\Delta W\) \(\quad \Delta U =-\Delta W\) Work done by gas is positive So \(\Delta U\) is negative…
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