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JEE Mains · Physics · STD 11 - 11. thermodynamics

Match List \(I\) with List \(II\) :
List \(I\) List \(II\)
\(A\) Isothermal Process \(I\) Work done by the gas decreases internal energy
\(B\) Adiabatic Process \(II\) No change in internal energy
\(C\) Isochoric Process \(III\) The heat absorbed goes partly to increase internal energy and partly to do work
\(D\) Isobaric Process \(IV\) No work is done on or by the gas
Choose the correct answer from the options given below :

  1. A \(A-II, B-I, C-III, D-IV\)
  2. B \(A-II, B-I, C-IV, D-III\)
  3. C \(A-I, B-II, C-IV, D-III\)
  4. D \(A-I, B-II, C-III, D-IV\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(A-II, B-I, C-IV, D-III\)

Step-by-step Solution

Detailed explanation

\(\Delta U = nC _{ v } \Delta T\) For isothermal process \(T\) is constant So \(\Delta U =0\) \(A \longrightarrow II\) Adiabatic process \(\Delta Q =0\) \(\Delta Q =\Delta U +\Delta W\) \(\quad \Delta U =-\Delta W\) Work done by gas is positive So \(\Delta U\) is negative…
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