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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2017
  • Hard
  • MCQ

Time \((T)\), velocity \((C)\) and angular momentum \((h)\) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

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Answer & Solution

Correct Answer

(A) \(\left[ M \right] = \left[ {{T^{ - 1}}\,{C^{ - 2}}\,h} \right]\)

Step-by-step Solution

Detailed explanation

Let mass related as \(M \propto \,{T^x}{C^y}{h^z}\)
\({M^1}{L^0}{T^0} = {\left( T \right)^x}{\left( {{L^1}{T^{ - 1}}} \right)^y}{\left( {{M^1}{L^2}{T^{ - 1}}} \right)^z}\)
\({M^1}{L^0}{T^0} = {M^z}{L^{y + 2z}} + {T^{x - y - z}}\)
\(z = 1\)
\(y + 2z = 0\)                      \(x - y - z = 0\)
\(y =  - 2\)                           \(x + 2 - 1 = 0\)
\(M = \left[ {{T^{ - 1}}{C^{ - 2}}{h^1}} \right]\)
 
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