JEE Mains · Physics · STD 11 - 3.1 vectors
In the cube of side \(a\) shown in the figure, the vector from the central point of the face \(ABOD\) to the central point of the face \(BEFO\) will be

- A \(\frac{1}{2}\,a\,\left( {\hat k - \hat i} \right)\)
- B \(\frac{1}{2}\,a\,\left( {\hat i - \hat k} \right)\)
- C \(\frac{1}{2}\,a\,\left( {\hat j - \hat i} \right)\)
- D \(\frac{1}{2}\,a\,\left( {\hat j - \hat k} \right)\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\,a\,\left( {\hat j - \hat i} \right)\)
Step-by-step Solution
Detailed explanation
Position vector of \(G\) is \(\overrightarrow{O G}=\frac{a \vec{i}}{2}+\frac{a}{2} \vec{k}\) Position vector of \(H\) is \(\overrightarrow{O H}=\frac{a}{2} \vec{j}+\frac{a}{2} \vec{k}\) \(\overrightarrow{G H}=\frac{a}{2}(\vec{j}-\vec{i})\)
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