JEE Mains · Physics · STD 12 - 1. Electric charges and fields
In the figure, a very large plane sheet of positive charge is shown. \(P _{1}\) and \(P _{2}\) are two points at distance \(l\) and \(2 \,l\) from the charge distribution. If \(\sigma\) is the surface charge density, then the magnitude of electric fields \(E_{1}\) and \(E_{2}\) at \(P _{1}\) and \(P _{2}\) respectively are
- A \(E _{1}=\sigma / \varepsilon_{0}, E _{2}=\sigma / 2 \varepsilon_{0}\)
- B \(E _{1}=2 \sigma / \varepsilon_{0}, E _{2}=\sigma / \varepsilon_{0}\)
- C \(E _{1}= E _{2}=\sigma / 2 \varepsilon_{0}\)
- D \(E _{1}= E _{2}=\sigma / \varepsilon_{0}\)
Answer & Solution
Correct Answer
(C) \(E _{1}= E _{2}=\sigma / 2 \varepsilon_{0}\)
Step-by-step Solution
Detailed explanation
As the sheet is very large \(\overrightarrow{ E }\) is independent of distance from it. Thus \(E _{1}= E _{2}=\frac{\sigma}{2 \varepsilon_{0}}\)
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