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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2022
  • Medium
  • MCQ

In the figure, a very large plane sheet of positive charge is shown. \(P _{1}\) and \(P _{2}\) are two points at distance \(l\) and \(2 \,l\) from the charge distribution. If \(\sigma\) is the surface charge density, then the magnitude of electric fields \(E_{1}\) and \(E_{2}\) at \(P _{1}\) and \(P _{2}\) respectively are

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Answer & Solution

Correct Answer

(C) \(E _{1}= E _{2}=\sigma / 2 \varepsilon_{0}\)

Step-by-step Solution

Detailed explanation

As the sheet is very large \(\overrightarrow{ E }\) is independent of distance from it.

Thus \(E _{1}= E _{2}=\frac{\sigma}{2 \varepsilon_{0}}\)

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