JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Two conducting circular loops \(A \) and \(B\) are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them is _______.
- A \(\frac{\mu_0 \pi a^2}{2 b}\)
- B \(\frac{\mu_0}{2 \pi} \cdot \frac{b^2}{a}\)
- C \(\frac{\mu_0 \pi b^2}{2 a}\)
- D \(\frac{\mu_0}{2 \pi} \cdot \frac{a^2}{b}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_0 \pi a^2}{2 b}\)
Step-by-step Solution
Detailed explanation
\(\phi=\mathrm{Mi}=\mathrm{BA}\) \(\Rightarrow \mathrm{Mi}=\frac{\mu_0 \mathrm{i}}{2 \mathrm{~b}} \pi \mathrm{a}^2\) \(\therefore \mathrm{M}=\frac{\mu_0 \pi \mathrm{a}^2}{2 \mathrm{~b}}\)
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