JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2023
- Easy
- Numerical
In Young's double slits experiment, the position of \(5^{\text {th }}\) bright fringe from the central maximum is \(5\,cm\). The distance between slits and screen is \(1\,m\) and wavelength of used monochromatic light is \(600\,nm\). The separation between the slits is \(........\mu m\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(60\)
Step-by-step Solution
Detailed explanation
Given
\(D =1\,m\)
\(\lambda=600 \times 10^{-9}\,m\)
\(n =5\)
\(\text { As } y _{ nth }=\frac{ n \lambda D }{ d }\)
\(\Rightarrow \frac{5 \times 600 \times 10^{-9} \times 1}{ d }=5 \times 10^{-2}\)
\(\Rightarrow d =\frac{5 \times 600 \times 10^{-9} \times 1}{5 \times 10^{-2}}=60 \times 10^{-6}\,m\)
\(\Rightarrow d =60\,\mu m\)
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