JEE Mains · Physics · STD 12 - 10. Wave optics
In Young's double slits experiment, the position of \(5^{\text {th }}\) bright fringe from the central maximum is \(5\,cm\). The distance between slits and screen is \(1\,m\) and wavelength of used monochromatic light is \(600\,nm\). The separation between the slits is \(........\mu m\)
- A \(60\)
- B \(48\)
- C \(12\)
- D \(36\)
Answer & Solution
Correct Answer
(A) \(60\)
Step-by-step Solution
Detailed explanation
Given \(D =1\,m\) \(\lambda=600 \times 10^{-9}\,m\) \(n =5\) \(\text { As } y _{ nth }=\frac{ n \lambda D }{ d }\) \(\Rightarrow \frac{5 \times 600 \times 10^{-9} \times 1}{ d }=5 \times 10^{-2}\)…
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