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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2023
  • Easy
  • Numerical

In Young's double slits experiment, the position of \(5^{\text {th }}\) bright fringe from the central maximum is \(5\,cm\). The distance between slits and screen is \(1\,m\) and wavelength of used monochromatic light is \(600\,nm\). The separation between the slits is \(........\mu m\)

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Answer & Solution

Correct Answer

(A) \(60\)

Step-by-step Solution

Detailed explanation

Given

\(D =1\,m\)

\(\lambda=600 \times 10^{-9}\,m\)

\(n =5\)

\(\text { As } y _{ nth }=\frac{ n \lambda D }{ d }\)

\(\Rightarrow \frac{5 \times 600 \times 10^{-9} \times 1}{ d }=5 \times 10^{-2}\)

\(\Rightarrow d =\frac{5 \times 600 \times 10^{-9} \times 1}{5 \times 10^{-2}}=60 \times 10^{-6}\,m\)

\(\Rightarrow d =60\,\mu m\)

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