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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2023
  • Medium
  • Numerical

\(n\) polarizing sheets are arranged such that each makes an angle \(45^{\circ}\) with the proceeding sheet. An unpolarized light of intensity \(I\) is incident into this arrangement. The output intensity is found to be \(\frac{I}{64}\). The value of \(n\) will be:

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Answer & Solution

Correct Answer

(B) \(6\)

Step-by-step Solution

Detailed explanation

After passing through first sheet

\(I_1=\frac{I}{2}\)

After passing through second sheet

\(I_2=I_1 \cos ^2\left(45^{\circ}\right)=\frac{I}{4}\)

After passing through \(n^{\text {th }}\) sheet

\(I_{ n }=\frac{I}{2^{ n }}=\frac{I}{64}\)

\(n=6\)

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