JEE Mains · Physics · STD 12 - 10. Wave optics
\(n\) polarizing sheets are arranged such that each makes an angle \(45^{\circ}\) with the proceeding sheet. An unpolarized light of intensity \(I\) is incident into this arrangement. The output intensity is found to be \(\frac{I}{64}\). The value of \(n\) will be:
- A \(3\)
- B \(6\)
- C \(5\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
After passing through first sheet \(I_1=\frac{I}{2}\) After passing through second sheet \(I_2=I_1 \cos ^2\left(45^{\circ}\right)=\frac{I}{4}\) After passing through \(n^{\text {th }}\) sheet \(I_{ n }=\frac{I}{2^{ n }}=\frac{I}{64}\) \(n=6\)
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