JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2023
- Medium
- Numerical
\(n\) polarizing sheets are arranged such that each makes an angle \(45^{\circ}\) with the proceeding sheet. An unpolarized light of intensity \(I\) is incident into this arrangement. The output intensity is found to be \(\frac{I}{64}\). The value of \(n\) will be:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
After passing through first sheet
\(I_1=\frac{I}{2}\)
After passing through second sheet
\(I_2=I_1 \cos ^2\left(45^{\circ}\right)=\frac{I}{4}\)
After passing through \(n^{\text {th }}\) sheet
\(I_{ n }=\frac{I}{2^{ n }}=\frac{I}{64}\)
\(n=6\)
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