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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

The magnetic field existing in a region is given by \(\overrightarrow{\mathrm{B}}=0.2(1+2 \mathrm{x}) \hat{\mathrm{k} T}\). A square loop of edge \(50 \mathrm{~cm}\) carrying \(0.5 \mathrm{~A}\) current is placed in \(x-y\) plane with its edges parallel to the \(x-y\) axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is___________ \(\mathrm{mN}\).

  1. A \(15\)
  2. B \(40\)
  3. C \(50\)
  4. D \(65\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(50\)

Step-by-step Solution

Detailed explanation

Force on segment parallel to \(\mathrm{x}\)-axis will cancel each other. Hence \(F_{\text {net }}\) will be due to portion parallel to \(y\)-axis. \(F=0.5 \times 0.5 \times 6 \times 0.2-0.5 \times 0.5 \times 0.2 \times 5\) \(=0.5 \times 0.5 \times 0.2\) \(=0.25 \times 0.2\)…
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