JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
The magnetic field existing in a region is given by \(\overrightarrow{\mathrm{B}}=0.2(1+2 \mathrm{x}) \hat{\mathrm{k} T}\). A square loop of edge \(50 \mathrm{~cm}\) carrying \(0.5 \mathrm{~A}\) current is placed in \(x-y\) plane with its edges parallel to the \(x-y\) axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is___________ \(\mathrm{mN}\).

- A \(15\)
- B \(40\)
- C \(50\)
- D \(65\)
Answer & Solution
Correct Answer
(C) \(50\)
Step-by-step Solution
Detailed explanation
Force on segment parallel to \(\mathrm{x}\)-axis will cancel each other. Hence \(F_{\text {net }}\) will be due to portion parallel to \(y\)-axis. \(F=0.5 \times 0.5 \times 6 \times 0.2-0.5 \times 0.5 \times 0.2 \times 5\) \(=0.5 \times 0.5 \times 0.2\) \(=0.25 \times 0.2\)…
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