JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2024
- Hard
- Numerical
The magnetic field existing in a region is given by \(\overrightarrow{\mathrm{B}}=0.2(1+2 \mathrm{x}) \hat{\mathrm{k} T}\). A square loop of edge \(50 \mathrm{~cm}\) carrying \(0.5 \mathrm{~A}\) current is placed in \(x-y\) plane with its edges parallel to the \(x-y\) axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is___________ \(\mathrm{mN}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(50\)
Step-by-step Solution
Detailed explanation
Force on segment parallel to \(\mathrm{x}\)-axis will cancel each other. Hence \(F_{\text {net }}\) will be due to portion parallel to \(y\)-axis.
\(F=0.5 \times 0.5 \times 6 \times 0.2-0.5 \times 0.5 \times 0.2 \times 5\)
\(=0.5 \times 0.5 \times 0.2\)
\(=0.25 \times 0.2\)
\(=50 \times 10^{-3} \mathrm{~N}\)
\(=50 \mathrm{mN}\)
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