JEE Mains · Physics · STD 12 - 10. Wave optics
In Young's double slit experiment, two slits \(S_1\) and \(S_2\) are ' \(d\) ' distance apart and the separation from slits to screen is \(D\) (as shown in figure). Now if two transparent slabs of equal thickness \(0.1\,mm\) but refractive index \(1.51\) and \(1.55\) are introduced in the path of beam \((\lambda=4000 \mathring A)\) from \(S_1\) and \(S_2\) respectively. The central bright fringe spot will shift by \(..........\) number of fringes.
- A \(11\)
- B \(9\)
- C \(7\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
Path difference at \(P\) be \(\Delta x\) \(\Delta x =\left(\mu_2-\mu_1\right) t\) \(=(1.55-1.51) 0.1\,mm\) \(=0.04 \times 10^{-4}\) \(\Delta x =4 \times 10^{-6}=4\,\mu m\) \(y =\frac{\Delta xD }{ d }=4 \times 10^{-6} \frac{ D }{ d }\) \(\{ y\) is the distance of central maxima…
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