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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2023
  • Medium
  • MCQ

Electric field in a certain region is given by \(\overrightarrow{ E }=\left(\frac{ A }{ x ^2} \hat{ i }+\frac{ B }{ y ^3} \hat{ j }\right)\). The \(SI\) unit of \(A\) and \(B\) are

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Correct Answer

(B) \(Nm ^2\, C ^{-1} ; Nm ^3 \,C ^{-1}\)

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Detailed explanation

\(\overrightarrow{ E }=\frac{ A }{ x ^2} \hat{ i }+\frac{ B }{ y ^3} \hat{ j }\)

\({\left[\frac{ A }{ x ^2}\right]= NC ^{-1} \Rightarrow[ A ]= Nm ^2 C ^{-1}}\)

\({\left[\frac{ B }{ y ^3}\right]= NC ^{-1} \Rightarrow[ B ]= Nm ^3 C ^{-1}}\)

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