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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Electric field in a certain region is given by \(\overrightarrow{ E }=\left(\frac{ A }{ x ^2} \hat{ i }+\frac{ B }{ y ^3} \hat{ j }\right)\). The \(SI\) unit of \(A\) and \(B\) are
- A \(Nm ^3\,C ^{-1} ; Nm ^2 \,C ^{-1}\)
- B \(Nm ^2\, C ^{-1} ; Nm ^3 \,C ^{-1}\)
- C \(Nm ^3 \,C ; Nm ^2 \,C\)
- D \(Nm ^2 \,C ; Nm ^3\, C\)
Answer & Solution
Correct Answer
(B) \(Nm ^2\, C ^{-1} ; Nm ^3 \,C ^{-1}\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ E }=\frac{ A }{ x ^2} \hat{ i }+\frac{ B }{ y ^3} \hat{ j }\) \({\left[\frac{ A }{ x ^2}\right]= NC ^{-1} \Rightarrow[ A ]= Nm ^2 C ^{-1}}\) \({\left[\frac{ B }{ y ^3}\right]= NC ^{-1} \Rightarrow[ B ]= Nm ^3 C ^{-1}}\)
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