JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Two identical thin rods of mass M kg and length L m are connected as shown in figure. Moment of inertia of the combined rod system about an axis passing through point P and perpendicular to the plane of the rods is \(\frac{x}{2} M L^2 kg m ^2\). The value of \(x\) is _________.
- A 12
- B 17
- C 13
- D 15
Answer & Solution
Correct Answer
(B) 17
Step-by-step Solution
Detailed explanation
\(I =\frac{ ML ^2}{3}+\left(\frac{ ML ^2}{12}+ ML ^2\right)\) \(=\frac{4 ML ^2+ ML ^2+12 ML ^2}{12}\) \(I =\frac{17}{12} ML ^2\) \(\therefore \quad x =17\)
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